3. first!
What you are missing is that if charging 1 cell then 0.05C is 100th of its 230,000mah. So you can end charge at its 3.650V at 2.3A.
230 X .05 = 11.5 not 2.3...
This is where you are losing me?
I didnt do the maths because I thought I knew the figures in my head!
You are correct. Again, that is basically the same result when you charge a single cell. I am trying to show you that it doesent make any difference what termination current you set here. On ONE cell.
As you charge at say 20 or 30 Amps then the voltage climbs very gradually from 3.2xx to 3.3xx over most of the usable charge at say 20A for 10 hours. And then voltage shoots up suddenly when full in a couple of mins. It doesent really climb at all much until the cell is basically 99% full and then it shoots up in a matter of a few mins to 3.55, 3.60, 3.65 or 3.8 and well above in seconds if you let it. In seconds. To stop that a good charger drops the charge current to whatever it takes. Or terminates charge.
Right up to this full point it will stay solidly in the CC stage at your fixed 30A. The flat part of the current Amp curves below. The difference between 11A, 5A, 2A etc end tail current is all irelevant. That cell is basically full (+99%) at their 3.65V level at this point whatever the current.
If you look at a charge curve for just 1 cell, or bunch of ALREADY balanced cells then you will see that the current basically stays at 30A or whatever you use, then drops off down like you rode a bicycle off a cliff. So 11A (or any) cut off current here results in a full cell. In order to keep that voltage at CV, you have to set a much lower cut off current. Guestimated at 800mA ish for 230Ah ones. (PL8.)
Look carefully at the CURRENT curve shape.
If the cells are
a) all balanced (so no long CV stage needed)
b) charger set to stop as soon as it sees the current drop to any low level (like in this case the 230ah cells suggested 0.05C).
Then it pretty much makes no difference at what point you cut off charge! When its full, and when CV stage occurs, its pretty much fully charged.
But if its not yet balanced you cant turn off the charger! Since the voltage will rapidly "settle" and drop and go below the point where balancing works at all.
So you need the following logic to fully charge and balance a pack!
End charge when
a. all cells are
balanced at 3.550V (less voltage is better for cells, but needs a little longer at CV.) Cut off at 11A, bad as this balancing hasnt yet happened!
b. final cell to reach (climb) to 3.550V needs some extra time at this lower voltage (to stop its voltage "settling" more than the other 7 that have been at CV for long time). And because of low current.
Why low current? A balancing charger, or a BMS will not allow the full cell(s) to exceed 3.550V and so in the case of a good hobby charger as soon as the first cell sees CV voltage it reduces the power (Amps) to enable the cell balancers 1A to keep that cell below the limit. That means that we are now at 1A charge while the rest catch up. If you set it to stop at 2.3A or 11A that also stops the other cells balancing or catching up. Depending on logic on charger/BMS.
Do you see this?